Breadth of the rectangle \(= 30 \,\rm{}cm\), Perimeter of a rectangle \(= 130 \,\rm{}cm.\), \(\begin{align}&\text{Perimeter of rectangle} \\ &= 2 \times \left( {{\rm{Length}} + {\rm{Breadth}}} \right)\end{align} \), \[\begin{align}130 &= 2 \times \left( {l + 30} \right)\\130 &= 2\,l + 60\\2\,l &= 130-60\\2\,l &= 70\\l &= \frac{{70}}{2}\\l &= 35\;\rm{cm}\end{align}\], \[\begin{align}&=\text{ Length} \times\text{ Breadth} \\ & = 35 \times 30 \\ &= 1050 \,\rm{cm^2}\end{align} \], A door of length \(2\,\rm{}m\) and breadth \(1\,\rm{}m\) is fitted in a wall. 1. A 3 m wide path runs outside and around a rectangular park of length 125 m and breadth 65 m. Find the area of the path. Once side of the square is known, its area can be calculated. We have provided Perimeter and Area Class 7 Maths MCQs Questions with Answers to help students understand the concept very well. Required fields are marked *. The new length and breadth of the garden when path is included is 100 m and 85 m respectively. The concepts of ‘Perimeter and Area’ are discussed in Chapter 11, Class 7 NCERT Maths. The concepts of ‘Perimeter and Area’ are discussed in Chapter 11, Class 7 NCERT Maths. Since same length of wire is used to from rectangle and square, Perimeter of square \(=\) perimeter of rectangle, \[\begin{align}4 \times {\rm{Side}} &= 2\left( {{\rm{Length}} + {\rm{Breadth}}} \right)\\4 \times {\rm{Side}} &= 2\left( {40 + 22} \right){\rm{ }}\\4 \times {\rm{Side}} &= 2 \times 62{\rm{ }}\\4 \times {\rm{Side}} &= 124\\{\rm{Side}} &= \frac{{124}}{4}\\{\rm{Side}} &= 31\;{\rm{cm}}\end{align}\], \[\begin{align}\text{Area of square}& = {\rm{side}} \times {\rm{side}}\\& = 31 \times 31\\ &= 961\;{\rm c{m^2}}\end{align}\], \(\begin{align}& \text{Area of rectangle} \\ &= {\rm{Length}} \times {\rm{Breadth}}\end{align} \), \(\begin{align} & = 40 \times 22\\&= 880{\rm{ }}{\rm\, c{m^2}}\end{align}\). Perimeter And Area For Class 7 - Displaying top 8 worksheets found for this concept.. Sorry!, This page is not available for now to bookmark. By referring to these Solutions, you will find a comprehensive study and a better understanding of the topic. Also, the concepts of measurement using a basic unit area of a square, rectangle, triangle, parallelogram, and circle, area between two rectangles and two concentric circles. Therefore, it is clear from the above that the figure square encloses more area than rectangle. 4. By referring to these Solutions, you will find a comprehensive study and a better understanding of the topic. MCQ Questions for Class 7 Maths with Answers were prepared based on the latest exam pattern. The perimeter of a rectangle is \(130 \,\rm{}cm.\) If the breadth of the rectangle is \(30 \,\rm{}cm, \) find its length. Perimeter of square park \(= 320\,\rm{}m\), Let length of each side of the square be \(a\), \[\begin{align}\text{Perimeter} &= \text{Sum of all the sides}\\320\,\rm m&= a + a + a + a\\4a &= 320 \, \rm m\\a &= 80\;\rm{m}\end{align}\], \[\begin{align}\therefore{\text{Area of square}}&= {\text{side}} \times {\rm{side}}\\ &= 80 \times 80{\rm{ }}\\ &= 6400{\rm{ }}{\rm \,m^2}\end{align}\]. Find the breadth of a rectangular plot of land, if its area is \(440 \,\rm{m^2}\) and the length is \(22 \,\rm{}m.\) Also, find its perimeter. By using the equations related to perimeter of square and rectangle, we can find the side of the square. Here we have covered Important Questions on Coordinate Geometry for Class 7 Maths subject.. Maths Important Questions Class 7 are given below.. NCERT Solutions for Class 7 Maths Exercise 11.4 Chapter 11 Perimeter and Area in simple PDF are available here. In the following figures, find the area of the shaded portions: To find the area of EFDC, first we have to find the area of ΔAEF, ΔEBC and rectangle ABCD, Area of rectangle ABCD = length × breadth, To find the area of ΔQTU, first we have to find the area of ΔSTU, ΔTPQ, ΔQRU and square PQRS, Area of ΔQTU = PQRS area – (ΔSTU + ΔTPQ + ΔQRU). 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